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- From: e120231@metu.edu.tr
- To: forum@abinit.org
- Subject: Re: Re: [abinit-forum] Convergence problem of tolmxf
- Date: Tue, 22 Feb 2005 09:49:44 +0100
Hello again,
Thanks for the comment
Here is my input for the FeTi (actually having a 221 space group) given to
abinit as 166
getwfk -1
optcell 2
ionmov 2
dilatmx 1.5
ecutsm 0.5
occopt 4
tsmear 0.02
kptopt 1
ngkpt 12 12 12
ecut 20.0
spgaxor 2
chkprim 0
spgroup 166
acell 5.4 5.4 5.4
angdeg 88 88 88
ntypat 2
znucl 26 22
natom 2
typat 1 2
xred
0.0 0.0 0.0
0.5 0.5 0.5
nstep 100
ntime 100
toldfe 1.0d-6
Here is a sample from the output file. Broyden step 10 has the lowest tolmxf
and the structure has converged to spacegroup 221.However after that in the
following Broyden steps (I made up to 100 Broyden step), there was deficiency
in the structure
occured. At the end of the 100th Broyden step ABINIT could not lower the
tolmxf and could not converge. I gave some of my ouput in below. I added the
tolmxf values taken from the log at the end of each Broyden step.
BROYDEN STEP NUMBER 8
------------------------------------------------------
iter Etot(hartree) deltaE(h) residm vres2 diffor maxfor
ETOT 1 -22.966536434279 -2.297E+01 5.725E-03 1.075E+00 0.000E+00
0.000E+00
ETOT 2 -22.966752587943 -2.162E-04 1.451E-03 9.344E-02 0.000E+00
0.000E+00
ETOT 3 -22.966772794562 -2.021E-05 3.964E-04 3.570E-03 0.000E+00
0.000E+00
ETOT 4 -22.966773419891 -6.253E-07 3.229E-04 1.845E-03 0.000E+00
0.000E+00
ETOT 5 -22.966771984994 1.435E-06 8.991E-05 7.082E-03 0.000E+00
0.000E+00
ETOT 6 -22.966773017082 -1.032E-06 2.229E-04 3.105E-03 0.000E+00
0.000E+00
ETOT 7 -22.966773062261 -4.518E-08 1.614E-04 2.968E-03 0.000E+00
0.000E+00
ETOT 8 -22.966761636600 1.143E-05 1.163E-04 4.872E-02 0.000E+00
0.000E+00
ETOT 9 -22.966772221172 -1.058E-05 4.374E-05 5.333E-03 0.000E+00
0.000E+00
ETOT 10 -22.966773638756 -1.418E-06 1.934E-04 5.279E-04 0.000E+00
0.000E+00
ETOT 11 -22.966773697939 -5.918E-08 3.614E-05 3.492E-04 0.000E+00
0.000E+00
ETOT 12 -22.966773727302 -2.936E-08 1.220E-04 3.207E-04 0.000E+00
0.000E+00
At SCF step 12, etot is converged :
for the second time, diff in etot= 2.936E-08 < toldfe= 1.000E-06
Cartesian components of stress tensor (hartree/bohr^3)
sigma(1 1)= -3.79291123E-06 sigma(3 2)= 0.00000000E+00
sigma(2 2)= -3.79290812E-06 sigma(3 1)= 0.00000000E+00
sigma(3 3)= -2.86019609E-06 sigma(2 1)= 0.00000000E+00
Unit cell characteristics :
acell= 5.6266321061E+00 5.6266321060E+00 5.6266321060E+00
rprim= 8.1649101156E-01 0.0000000000E+00 5.7735814538E-01
-4.0824550579E-01 7.0710195796E-01 5.7735814539E-01
-4.0824550579E-01 -7.0710195796E-01 5.7735814539E-01
ucvol= 1.7813348310E+02 Bohr^3
lengths= 5.6266321061E+00 5.6266321060E+00 5.6266321060E+00 Bohr
angles (23,13,12)= 89.99921837 89.99921837 89.99921837 degrees
Cartesian coordinates (bohr)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
8.88178419700125E-16 0.00000000000000E+00 4.87287281626526E+00
Cartesian forces (hart/bohr); max,rms= 0.00000E+00 0.00000E+00 (free atoms)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
At the end of Broyden step 8, total energy= -2.29667737273019E+01 Ha.
\ fconv : at Broyd/MD step 8, gradients have not converged yet.
\
\ max grad (force/stress) = 3.7929E-04 > tolmxf= 5.0000E-05 ha/bohr (free
atoms) \
BROYDEN STEP NUMBER 9
------------------------------------------------------
iter Etot(hartree) deltaE(h) residm vres2 diffor maxfor
ETOT 1 -22.966749542588 -2.297E+01 1.660E-05 1.099E-01 0.000E+00
0.000E+00
ETOT 2 -22.966773838699 -2.430E-05 2.117E-05 2.583E-04 0.000E+00
0.000E+00
ETOT 3 -22.966773871077 -3.238E-08 5.448E-05 1.309E-04 0.000E+00
0.000E+00
ETOT 4 -22.966773892115 -2.104E-08 2.181E-05 7.391E-05 0.000E+00
0.000E+00
At SCF step 4, etot is converged :
for the second time, diff in etot= 2.104E-08 < toldfe= 1.000E-06
Cartesian components of stress tensor (hartree/bohr^3)
sigma(1 1)= -3.79425250E-07 sigma(3 2)= 0.00000000E+00
sigma(2 2)= -3.79415455E-07 sigma(3 1)= 0.00000000E+00
sigma(3 3)= -1.11299890E-06 sigma(2 1)= 0.00000000E+00
Unit cell characteristics :
acell= 5.6272428877E+00 5.6272428874E+00 5.6272428874E+00
rprim= 8.1648523902E-01 0.0000000000E+00 5.7736630873E-01
-4.0824261953E-01 7.0709695877E-01 5.7736630877E-01
-4.0824261953E-01 -7.0709695877E-01 5.7736630877E-01
ucvol= 1.7819149941E+02 Bohr^3
lengths= 5.6272428877E+00 5.6272428874E+00 5.6272428874E+00 Bohr
angles (23,13,12)= 89.99840822 89.99840823 89.99840823 degrees
Cartesian coordinates (bohr)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
8.88178419700125E-16 0.00000000000000E+00 4.87347068165397E+00
Cartesian forces (hart/bohr); max,rms= 0.00000E+00 0.00000E+00 (free atoms)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
At the end of Broyden step 9, total energy= -2.29667738921148E+01 Ha.
\ fconv : at Broyd/MD step 9, gradients have not converged yet.
\
\ max grad (force/stress) = 1.1130E-04 > tolmxf= 5.0000E-05 ha/bohr (free
atoms) \
BROYDEN STEP NUMBER 10
------------------------------------------------------
iter Etot(hartree) deltaE(h) residm vres2 diffor maxfor
ETOT 1 -22.966773232412 -2.297E+01 1.621E-05 3.057E-03 0.000E+00
0.000E+00
ETOT 2 -22.966773901861 -6.694E-07 2.760E-05 1.889E-05 0.000E+00
0.000E+00
ETOT 3 -22.966773903563 -1.702E-09 2.011E-05 1.411E-05 0.000E+00
0.000E+00
At SCF step 3, etot is converged :
for the second time, diff in etot= 1.702E-09 < toldfe= 1.000E-06
Cartesian components of stress tensor (hartree/bohr^3)
sigma(1 1)= -8.03196989E-07 sigma(3 2)= 0.00000000E+00
sigma(2 2)= -8.03153585E-07 sigma(3 1)= 0.00000000E+00
sigma(3 3)= 9.68692273E-08 sigma(2 1)= 0.00000000E+00
Unit cell characteristics :
acell= 5.6274587436E+00 5.6274587422E+00 5.6274587422E+00
rprim= 8.1645760620E-01 0.0000000000E+00 5.7740538383E-01
-4.0822880320E-01 7.0707302791E-01 5.7740538398E-01
-4.0822880320E-01 -7.0707302791E-01 5.7740538398E-01
ucvol= 1.7821200368E+02 Bohr^3
lengths= 5.6274587436E+00 5.6274587422E+00 5.6274587422E+00 Bohr
angles (23,13,12)= 89.99453018 89.99453021 89.99453021 degrees
Cartesian coordinates (bohr)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
8.88178419700125E-16 0.00000000000000E+00 4.87398746376860E+00
Cartesian forces (hart/bohr); max,rms= 0.00000E+00 0.00000E+00 (free atoms)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
At the end of Broyden step 10, total energy= -2.29667739035632E+01 Ha.
\ fconv : at Broyd/MD step 10, gradients have not converged yet.
\
\ max grad (force/stress) = 8.0320E-05 > tolmxf= 5.0000E-05 ha/bohr (free
atoms) \
BROYDEN STEP NUMBER 11
------------------------------------------------------
iter Etot(hartree) deltaE(h) residm vres2 diffor maxfor
ETOT 1 -22.966772375944 -2.297E+01 1.043E-05 6.920E-03 0.000E+00
0.000E+00
ETOT 2 -22.966773904921 -1.529E-06 1.359E-05 1.400E-05 0.000E+00
0.000E+00
ETOT 3 -22.966773906902 -1.982E-09 2.790E-05 8.399E-06 0.000E+00
0.000E+00
ETOT 4 -22.966773905196 1.706E-09 1.230E-05 2.187E-05 0.000E+00
0.000E+00
At SCF step 4, etot is converged :
for the second time, diff in etot= 1.706E-09 < toldfe= 1.000E-06
Cartesian components of stress tensor (hartree/bohr^3)
sigma(1 1)= 5.36184946E-07 sigma(3 2)= 0.00000000E+00
sigma(2 2)= 5.36365673E-07 sigma(3 1)= 0.00000000E+00
sigma(3 3)= 1.93434811E-06 sigma(2 1)= 0.00000000E+00
Unit cell characteristics :
acell= 5.6276024340E+00 5.6276024282E+00 5.6276024282E+00
rprim= 8.1646025568E-01 0.0000000000E+00 5.7740163742E-01
-4.0823012826E-01 7.0707532187E-01 5.7740163801E-01
-4.0823012826E-01 -7.0707532187E-01 5.7740163801E-01
ucvol= 1.7822565536E+02 Bohr^3
lengths= 5.6276024340E+00 5.6276024282E+00 5.6276024282E+00 Bohr
angles (23,13,12)= 89.99490191 89.99490203 89.99490203 degrees
Cartesian coordinates (bohr)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
8.88178419700125E-16 0.00000000000000E+00 4.87408029018099E+00
Cartesian forces (hart/bohr); max,rms= 0.00000E+00 0.00000E+00 (free atoms)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
At the end of Broyden step 11, total energy= -2.29667739051959E+01 Ha.
\ fconv : at Broyd/MD step 11, gradients have not converged yet.
\
\ max grad (force/stress) = 1.9343E-04 > tolmxf= 5.0000E-05 ha/bohr (free
atoms) \
BROYDEN STEP NUMBER 12
------------------------------------------------------
iter Etot(hartree) deltaE(h) residm vres2 diffor maxfor
ETOT 1 -22.966772944689 -2.297E+01 2.125E-01 4.420E-03 0.000E+00
0.000E+00
ETOT 2 -22.966773918439 -9.737E-07 1.869E-01 8.946E-06 0.000E+00
0.000E+00
ETOT 3 -22.966773919149 -7.099E-10 1.050E-01 9.791E-06 0.000E+00
0.000E+00
At SCF step 3, etot is converged :
for the second time, diff in etot= 7.099E-10 < toldfe= 1.000E-06
Cartesian components of stress tensor (hartree/bohr^3)
sigma(1 1)= 3.46496172E-07 sigma(3 2)= 0.00000000E+00
sigma(2 2)= 3.46960283E-07 sigma(3 1)= 0.00000000E+00
sigma(3 3)= 1.53640669E-06 sigma(2 1)= 0.00000000E+00
Unit cell characteristics :
acell= 5.6275451220E+00 5.6275451072E+00 5.6275451072E+00
rprim= 8.1648118434E-01 0.0000000000E+00 5.7737204264E-01
-4.0824059324E-01 7.0709344549E-01 5.7737204416E-01
-4.0824059324E-01 -7.0709344549E-01 5.7737204416E-01
ucvol= 1.7822021139E+02 Bohr^3
lengths= 5.6275451220E+00 5.6275451072E+00 5.6275451072E+00 Bohr
angles (23,13,12)= 89.99783888 89.99783918 89.99783918 degrees
Cartesian coordinates (bohr)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
4.44089209850063E-16 0.00000000000000E+00 4.87378083321050E+00
Cartesian forces (hart/bohr); max,rms= 0.00000E+00 0.00000E+00 (free atoms)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
At the end of Broyden step 12, total energy= -2.29667739191489E+01 Ha.
\ fconv : at Broyd/MD step 12, gradients have not converged yet.
\
\ max grad (force/stress) = 1.5364E-04 > tolmxf= 5.0000E-05 ha/bohr (free
atoms) \
BROYDEN STEP NUMBER 13
------------------------------------------------------
iter Etot(hartree) deltaE(h) residm vres2 diffor maxfor
ETOT 1 -22.966770697534 -2.297E+01 4.019E-04 1.409E-02 0.000E+00
0.000E+00
ETOT 2 -22.966773793070 -3.096E-06 8.139E-05 2.587E-04 0.000E+00
0.000E+00
ETOT 3 -22.966773818697 -2.563E-08 5.437E-05 1.875E-04 0.000E+00
0.000E+00
ETOT 4 -22.966773751889 6.681E-08 1.164E-04 5.304E-04 0.000E+00
0.000E+00
At SCF step 4, etot is converged :
for the second time, diff in etot= 6.681E-08 < toldfe= 1.000E-06
Cartesian components of stress tensor (hartree/bohr^3)
sigma(1 1)= -2.54070334E-06 sigma(3 2)= 0.00000000E+00
sigma(2 2)= -2.53374477E-06 sigma(3 1)= 0.00000000E+00
sigma(3 3)= -4.76857630E-06 sigma(2 1)= 0.00000000E+00
Unit cell characteristics :
acell= 5.6273292852E+00 5.6273290632E+00 5.6273290632E+00
rprim= 8.1658925316E-01 0.0000000000E+00 5.7721918855E-01
-4.0829464268E-01 7.0718700981E-01 5.7721921131E-01
-4.0829464268E-01 -7.0718700981E-01 5.7721921131E-01
ucvol= 1.7819967948E+02 Bohr^3
lengths= 5.6273292852E+00 5.6273290632E+00 5.6273290632E+00 Bohr
angles (23,13,12)= 90.01300234 90.01300686 90.01300686 degrees
Cartesian coordinates (bohr)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
-2.66453525910038E-15 0.00000000000000E+00 4.87230366551748E+00
Cartesian forces (hart/bohr); max,rms= 0.00000E+00 0.00000E+00 (free atoms)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
At the end of Broyden step 13, total energy= -2.29667737518891E+01 Ha.
\ fconv : at Broyd/MD step 13, gradients have not converged yet.
\
\ max grad (force/stress) = 4.7686E-04 > tolmxf= 5.0000E-05 ha/bohr (free
atoms) \
BROYDEN STEP NUMBER 14
------------------------------------------------------
iter Etot(hartree) deltaE(h) residm vres2 diffor maxfor
ETOT 1 -22.966752502643 -2.297E+01 1.631E-02 9.707E-02 0.000E+00
0.000E+00
ETOT 2 -22.966773882587 -2.138E-05 4.831E-03 1.137E-04 0.000E+00
0.000E+00
ETOT 3 -22.966773881769 8.178E-10 4.082E-04 1.484E-04 0.000E+00
0.000E+00
ETOT 4 -22.966773904397 -2.263E-08 4.664E-03 6.777E-05 0.000E+00
0.000E+00
At SCF step 4, etot is converged :
for the second time, diff in etot= 2.263E-08 < toldfe= 1.000E-06
Cartesian components of stress tensor (hartree/bohr^3)
sigma(1 1)= 4.72936586E-07 sigma(3 2)= 0.00000000E+00
sigma(2 2)= 4.82350876E-07 sigma(3 1)= 0.00000000E+00
sigma(3 3)= -2.38868438E-06 sigma(2 1)= 0.00000000E+00
Unit cell characteristics :
acell= 5.6275246441E+00 5.6275243438E+00 5.6275243438E+00
rprim= 8.1652511673E-01 0.0000000000E+00 5.7730991136E-01
-4.0826258015E-01 7.0713145619E-01 5.7730994217E-01
-4.0826258015E-01 -7.0713145619E-01 5.7730994217E-01
ucvol= 1.7821824683E+02 Bohr^3
lengths= 5.6275246441E+00 5.6275243438E+00 5.6275243438E+00 Bohr
angles (23,13,12)= 90.00399882 90.00400494 90.00400494 degrees
Cartesian coordinates (bohr)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
-4.44089209850063E-16 0.00000000000000E+00 4.87323863023248E+00
Cartesian forces (hart/bohr); max,rms= 0.00000E+00 0.00000E+00 (free atoms)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
At the end of Broyden step 14, total energy= -2.29667739043972E+01 Ha.
\ fconv : at Broyd/MD step 14, gradients have not converged yet.
\
\ max grad (force/stress) = 2.3887E-04 > tolmxf= 5.0000E-05 ha/bohr (free
atoms) \
BROYDEN STEP NUMBER 15
------------------------------------------------------
iter Etot(hartree) deltaE(h) residm vres2 diffor maxfor
ETOT 1 -22.966620945274 -2.297E+01 3.416E-02 6.434E-01 0.000E+00
0.000E+00
ETOT 2 -22.966745907294 -1.250E-04 1.728E-03 8.734E-02 0.000E+00
0.000E+00
ETOT 3 -22.966759805382 -1.390E-05 8.270E-03 2.936E-02 0.000E+00
0.000E+00
ETOT 4 -22.966762134786 -2.329E-06 7.854E-04 2.068E-02 0.000E+00
0.000E+00
ETOT 5 -22.966764963814 -2.829E-06 1.230E-03 1.387E-02 0.000E+00
0.000E+00
ETOT 6 -22.966766051589 -1.088E-06 1.217E-03 1.019E-02 0.000E+00
0.000E+00
ETOT 7 -22.966767197059 -1.145E-06 2.928E-03 4.809E-03 0.000E+00
0.000E+00
ETOT 8 -22.966767949942 -7.529E-07 1.126E-03 9.867E-04 0.000E+00
0.000E+00
ETOT 9 -22.966768053860 -1.039E-07 1.428E-03 5.901E-04 0.000E+00
0.000E+00
At SCF step 9, etot is converged :
for the second time, diff in etot= 1.039E-07 < toldfe= 1.000E-06
Cartesian components of stress tensor (hartree/bohr^3)
sigma(1 1)= -6.71257559E-06 sigma(3 2)= 0.00000000E+00
sigma(2 2)= -6.64016914E-06 sigma(3 1)= 0.00000000E+00
sigma(3 3)= 1.84934659E-05 sigma(2 1)= 0.00000000E+00
Unit cell characteristics :
acell= 5.6292106787E+00 5.6292083701E+00 5.6292083701E+00
rprim= 8.1544723680E-01 0.0000000000E+00 5.7883141241E-01
-4.0772378561E-01 7.0619773140E-01 5.7883164980E-01
-4.0772378561E-01 -7.0619773140E-01 5.7883164980E-01
ucvol= 1.7837659126E+02 Bohr^3
lengths= 5.6292106787E+00 5.6292083701E+00 5.6292083701E+00 Bohr
angles (23,13,12)= 89.85277671 89.85282377 89.85282377 degrees
Cartesian coordinates (bohr)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
2.22044604925031E-14 0.00000000000000E+00 4.88754595191213E+00
Cartesian forces (hart/bohr); max,rms= 0.00000E+00 0.00000E+00 (free atoms)
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
0.00000000000000E+00 0.00000000000000E+00 0.00000000000000E+00
At the end of Broyden step 15, total energy= -2.29667680538599E+01 Ha.
fconv : at Broyd/MD step 15, gradients have not converged yet.
max grad (force/stress) = 1.8493E-03 > tolmxf= 5.0000E-05 ha/bohr (free
atoms)
- Re: Re: [abinit-forum] Convergence problem of tolmxf, e120231, 02/22/2005
- Re :[abinit-forum] Convergence problem of tolmxf, Michel Côté, 02/22/2005
- Re :[abinit-forum] Convergence problem of tolmxf, ALPER KINACI, 02/23/2005
- Re :Re :[abinit-forum] Convergence problem of tolmxf, Cote Michel, 02/23/2005
- Re :[abinit-forum] Convergence problem of tolmxf, ALPER KINACI, 02/23/2005
- Re :[abinit-forum] Convergence problem of tolmxf, Michel Côté, 02/22/2005
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