forum@abinit.org
Subject: The ABINIT Users Mailing List ( CLOSED )
List archive
- From: 张 <zhangting@pku.edu.cn>
- To: forum@abinit.org
- Subject: Thanks!
- Date: Mon, 10 Apr 2006 22:43:26 +0800
- Priority: normal
Thanks very much for your help! By using default rprim
(1,0,0;0,1,0;0,0,1), the code can find a P1 symmetry, thanks a lot!
your suggestion is very useful.
My k-point setting is from CASTEP..for I'm also a CASTEP user. In
CASTEP's settings,this cell(about 15Ax15Ax2.4A) need a 2x2x10's
mesh,for the k-space grid density probably being 0.03~0.04
(1/Angstrom).In fact I don't clearly know whether there are
differences between these two codes in k-space grid representation,
and maybe I don't exactly understand your question yet.Do you mean my
k-point mesh density is too high or too low? or my unit cell is too
small?
Zhang Ting
Apr.10th 2006
>Hi!
> I also try to optimize the geometry 7_0 CNT but in my case I use
default value of rprim (1 0 0; 0 1 0; 0 0 1) see my input file and
sketch of unit cell in attachment. In this case abinit calculates the
space group base on atoms position. I can advise you use default value
of rprim and see what happened. Also, use less value of toldff, your
calculation will be faster, then you specify more precisely.
>
> On the other hand I am confused with ngkpt?
> Can you explain to my how you choose ngkpt? Why is it 2 2 10, what
criteria for this?
>
>
>
>Yaroslav Shtogun
>*********************************
>College Art & Science
>University of South Florida
>4202 East Fowler Ave
>Tampa, FL 33620-5700
>USA
>
>Cell: (813) 401-0016
>Tel: (813) 974-8489
>Fax: (813) 974-5813
- Thanks!, 张, 04/10/2006
Archive powered by MHonArc 2.6.16.