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The orthorhombic phase Amm2(#38)


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  • From: scabuk@cu.edu.tr
  • To: forum@abinit.org
  • Subject: The orthorhombic phase Amm2(#38)
  • Date: Fri, 19 Jan 2007 10:16:45 +0100

Dear abinit users,

I would like to calculate some structure parameters the orthorhombic phase
Amm2(38) of KNbO3. But I couldn't get the space group Amm2. Output file was
given me the space group Pmm2 (#25). I can use LDA pseudopotentials. How can
I get the space group Amm2 ? I will be very glad if you could help me.
Thank you for your attention.

Best Regards.

Suleyman Cabuk
email:scabuk@cu.edu.tr



My input file:

# Crystalline KNbO3 : computation of the total energy
#Definition of the k-point grids
kptopt 1

ngkpt 8 8 8

getwfk -1

ecut 35.0

acell 10.766 7.504 10.809
angdeg 90.0 90.0 90.0

rprim 1.0 0.0 0.0 # or 1 0 0
0.0 0.5 -0.5 # 0 1 0
0.0 0.5 0.5 # 0 0 1

ntypat 3
znucl 19 41 8

natom 10
typat 1 1 2 2 3 3 3 3 3 3
xred
0.0 0.5 0.517 #K1
0.0 0.0 0.017 #K2
0.0 0.0 0.0 #Nb1
0.0 0.5 0.5 #Nb2
0.0 0.5 0.021 #OI_1
0.0 0.0 0.521 #OI_2
0.254 0.0 0.285 #OII_1
0.746 0.0 0.285 #OII_2
0.254 0.0 0.785 #OIII_3
0.746 0.0 0.785 #OII_4

nstep 1000
toldfe 1.0d-6

Output file:
Symmetries : space group Pm m 2 (# 25); Bravais oP (primitive ortho.)
===============================================================================
Values of the parameters that define the memory need of the present run
intxc = 0 ionmov = 0 iscf = 5 ixc =
7
lmnmax = 4 lnmax = 4 mband = 26 mffmem =
1
P mgfft = 60 mkmem = 64 mpssoang= 4 mpw =
4340
mqgrid = 1201 natom = 10 nfft = 81000 nkpt =
64
nloalg = 4 nspden = 1 nspinor = 1 nsppol =
1
nsym = 4 n1xccc = 2501 ntypat = 3 occopt =
1
===============================================================================





  • The orthorhombic phase Amm2(#38), scabuk, 01/19/2007

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