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- From: "duan_semi" <abinit_duan@126.com>
 - To: "forum" <forum@abinit.org>
 - Subject: spontaneous polarization!
 - Date: Fri, 27 Apr 2007 21:37:45 +0800 (CST)
 
Hello everyone,
         I want to calculate the spontaneous polarization of ZnO . The attached  is the input file. After 
calculation i get the following results:
  Computing the polarization (Berry phase) for reciprocal vector:
0.00000 0.00000 0.16667 (in reduced coordinates)
0.00000 0.00000 0.01736 (in cartesian coordinates - atomic units)
From band number 1 to band number 18
0.00000 0.00000 0.16667 (in reduced coordinates)
0.00000 0.00000 0.01736 (in cartesian coordinates - atomic units)
From band number 1 to band number 18
 Summary of the results
Electronic Berry phase 8.785423599E-01
Ionic phase -3.966504761E-01
Total phase 4.818918837E-01
Remapping in [-1,1] 4.818918837E-01
Electronic Berry phase 8.785423599E-01
Ionic phase -3.966504761E-01
Total phase 4.818918837E-01
Remapping in [-1,1] 4.818918837E-01
           Polarization     1.573749771E-02 (a.u. of charge)/bohr^2
Polarization 9.004171942E-01 C/m^2
I do not know how to get the spontaneous polarization. Any suggestion will be helpful!
Polarization 9.004171942E-01 C/m^2
I do not know how to get the spontaneous polarization. Any suggestion will be helpful!
DeWei
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Attachment:
zno.in
Description: Binary data
- spontaneous polarization!, duan_semi, 04/27/2007
- Re: [abinit-forum] spontaneous polarization!, Xavier Gonze, 04/30/2007
 
 
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