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- From: "Kim Allen" <hydeng2007@gmail.com>
- To: "forum@abinit.org" <forum@abinit.org>
- Subject: How to set the xred of the Zn(CN)2?
- Date: Mon, 28 May 2007 14:52:40 +0800
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Dear Abiniter,
The Wyckoff position of Zn(CN)2 is as following:
---------------------------------------------------
Atom # OX SITE x y z SOF H ITF(U)
Zn 1 +2 2 a 0.25 0.25 0.25 1. 0 0.0510(3)
N 1 -3 8 e 0.05587(19) 0.44413(19) 0.05587(19) 0.5 0 0.0603(6)
C 1 +2 8 e 0.05587(19) 0.44413(19) 0.05587(19) 0.5 0 0.0603(6)
Zn 1 +2 2 a 0.25 0.25 0.25 1. 0 0.0510(3)
N 1 -3 8 e 0.05587(19) 0.44413(19) 0.05587(19) 0.5 0 0.0603(6)
C 1 +2 8 e 0.05587(19) 0.44413(19) 0.05587(19) 0.5 0 0.0603(6)
------------------------------------------------
From the above Wyckoff position, we can find that the N atom and the C atom have the same Wyckoff coordinate, which bring me into trouble. How to set the Xred of the N atom and the C atom?When I set the 4 N atoms and 4 C atoms at the 8e postion, the calculated SG(space group) is not 224. What's wrong with me?
Thanks!
Kim Allen
- How to set the xred of the Zn(CN)2?, Kim Allen, 05/28/2007
- Re: [abinit-forum] How to set the xred of the Zn(CN)2?, Masayoshi Mikami, 05/28/2007
- Re: [abinit-forum] How to set the xred of the Zn(CN)2?, Sharat Chandra, 05/29/2007
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