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Re: [abinit-forum] nkpt problem


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  • From: Hua Bao <hbao@purdue.edu>
  • To: forum@abinit.org
  • Subject: Re: [abinit-forum] nkpt problem
  • Date: Thu, 23 Aug 2007 12:48:30 -0400

Dear Matthieu,

Thank you for your reply. I changed the input file and use abinis to do the calculation. However, it just got running for a long time and no output was there. If I killed the job, there was even no output. The out file and log file were just nothing.
It this a bug or something? Or is there any compiling problem? At least there should be some output in the log file.

Thanks,
Hua


Matthieu Verstraete wrote:

Hello Hua,

1) you should not set chkprim 0; use an irreducible unit cell unless you are certain of what you are doing

2) The default kpt shift is 1 shift at 0.5 0.5 0.5. This could be what breaks the symmetries, as you are in a hexagonal, not a cubic system. Specify shiftk explicitly as 0.0 0.0 0.5 for hex systems, or even 0.0 0.0 0.0. If you include 0.5 0.5 0.5, a single kpt shift is probably not enough. See the tutorials and tests (in v1) on generating good kpt grids.
Depending on what you are doing the code sometimes imposes that the kpt grid has the full lattice symmetry. In any case this is always a good idea, and is broken if your shift can be rotated out of the kpt grid by a symop.

In your case the full point group symmetry appears to be P1, which I think is wrong for corundum (probably your xangst are not precise enough - should probably try natrd and associated variables). For the kpoints the bravais lattice symmetries are used, ie for the hexagonal cell.

Matthieu





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