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- From: David Tompsett <dat36@cam.ac.uk>
- To: forum@abinit.org
- Subject: Re: [abinit-forum] Gamma Phonon Calculation Fails
- Date: Thu, 30 Oct 2008 11:52:04 +0000
Thanks PMA for the suggestion, but when I look in the error files for each node they are empty.
Do you have any other suggestions as to how I might find the error.
Best,
David.
Anglade Pierre-Matthieu wrote:
Hi,
When you run in parallel, every process opens its own log file and
sometime that's where you will find the error messages. Have you had a
look at those log files ?
regards
PMA
On Wed, Oct 29, 2008 at 12:10 PM, <dat36@cam.ac.uk> wrote:
Dear All,
I am trying to calculate the phonon frequencies at Gamma for my
metallic system using the prescription of the Response Function Tutorial 1 by
calculating the dynamical matrix at Gamma.
I have calculated the input ground state wavefunctions with the input file:
# Computation of the ground state WFK for input into rf calcs.
# First, a SCF density computation.
ndtset 1
#Dataset 1 : usual self-consistent calculation
kptopt1 1 # Option for the automatic generation of k points,
# taking into account the symmetry
#Definition of the k-point grid
kptrlatt -4 4 4 # In cartesian coordinates, this grid is simple cubic,
and
4 -4 4 # actually corresponds to the so-called 8x8x8
Monkhorst-Pack grid.
4 4 -4 # It might as well be obtained through the use of
# ngkpt, nshiftk and shiftk .
prtden1 1 # Print the density, for use by dataset 2
toldfe1 1.0d-8
#Definition of the unit cell
acell 3*1.8897 # This is equivalent to 1 Angstrom each
rprim
5.137609105410803 -2.966200000000002 0.000000000000000
0.000000000000000 5.932400000000000 0.000000000000000
0.000000000000000 0.000000000000000 6.410500000000000
#Definition of the atom types
ntypat 3 # There is only one type of atom
znucl 8 47 82 # The keyword "znucl" refers to the atomic number of
the
# possible type(s) of atom. The pseudopotential(s)
# mentioned in the "files" file must correspond
# to the type(s) of atom. Here, the only type is Silicon.
#Definition of the atoms
natom 13 # There are two atoms
typat 1 1 1 1 1 1 2 2 2 2 2 3 3 # They both are of type 1, that is,
Silicon.
xred # This keyword indicate that the location of the atoms
# will follow, one triplet of number for each atom
# Triplet giving the REDUCED coordinate of atom 1.
# Triplet giving the REDUCED coordinate of atom 2.
0.6222000122070313 0.0000000000000001 0.6888999938964855
-0.0000000000000001 0.6222000122070313 0.6888999938964855
-0.6222000122070311 -0.6222000122070314 0.6888999938964854
-0.0000000000000001 -0.6222000122070314 -0.6888999938964855
-0.6222000122070311 0.0000000000000001 -0.6888999938964855
0.6222000122070313 0.6222000122070313 -0.6888999938964854
0.0000000000000000 0.0000000000000000 0.2413000017404568
0.0000000000000000 0.0000000000000000 -0.2413000017404568
0.5000000000000000 -0.0000000000000000 0.0000000000000000
0.0000000000000000 0.5000000000000001 0.0000000000000000
-0.5000000000000000 -0.5000000000000001 -0.0000000000000000
0.6666666666666667 0.3333333333333334 0.5000000000000001
-0.6666666666666667 -0.3333333333333334 -0.5000000000000001
#Definition of the planewave basis set
ecut 100.0 # Maximal kinetic energy cut-off, in Hartree
nband 70
#Definition of the SCF procedure
nstep 100 # Maximal number of SCF cycles
# Although this is not mandatory, it is worth to
# precondition the SCF cycle. The model dielectric
# function used as the standard preconditioner
# is described in the "dielng" input variable section.
# Here, we follow the prescription for bulk silicon.
occopt 7
tsmear 0.007
---------------------------------------------------------------------------------------------
Then the response function calculation with the input:
# Crystalline Ag5Pb2O6: computation of the dynamical matrix at Gamma
#
#Response-function calculation, with q=0
rfphon 1 # Will consider phonon-type perturbation
rfatpol 1 13 # All the atoms will be displaced
rfdir 1 1 1 # Along all reduced coordinate axis
nqpt 1 # One wavevector is to be considered
qpt 0 0 0 # This wavevector is q=0 (Gamma)
kptopt 2 # Automatic generation of k points, taking
# into account the time-reversal symmetry only
tolvrs 1.0d-8 # SCF stopping criterion
iscf 5 # Self-consistent calculation, using algorithm 5
irdwfk 1 # Read the ground-state wavefunctions
#######################################################################
#Common input variables
#Definition of the unit cell
acell 3*1.8897 # This is equivalent to 1 Angstrom each
rprim
5.137609105410803 -2.966200000000002 0.000000000000000
0.000000000000000 5.932400000000000 0.000000000000000
0.000000000000000 0.000000000000000 6.410500000000000
#Definition of the atom types
ntypat 3 # There is only one type of atom
znucl 8 47 82 # The keyword "znucl" refers to the atomic number of
the
# possible type(s) of atom. The pseudopotential(s)
# mentioned in the "files" file must correspond
# to the type(s) of atom. Here, the only type is Silicon.
#Definition of the atoms
natom 13 # There are two atoms
typat 1 1 1 1 1 1 2 2 2 2 2 3 3 # They both are of type 1, that is,
Silicon.
xred # This keyword indicate that the location of the atoms
# will follow, one triplet of number for each atom
# Triplet giving the REDUCED coordinate of atom 1.
# Triplet giving the REDUCED coordinate of atom 2.
0.6222000122070313 0.0000000000000001 0.6888999938964855
-0.0000000000000001 0.6222000122070313 0.6888999938964855
-0.6222000122070311 -0.6222000122070314 0.6888999938964854
-0.0000000000000001 -0.6222000122070314 -0.6888999938964855
-0.6222000122070311 0.0000000000000001 -0.6888999938964855
0.6222000122070313 0.6222000122070313 -0.6888999938964854
0.0000000000000000 0.0000000000000000 0.2413000017404568
0.0000000000000000 0.0000000000000000 -0.2413000017404568
0.5000000000000000 -0.0000000000000000 0.0000000000000000
0.0000000000000000 0.5000000000000001 0.0000000000000000
-0.5000000000000000 -0.5000000000000001 -0.0000000000000000
0.6666666666666667 0.3333333333333334 0.5000000000000001
-0.6666666666666667 -0.3333333333333334 -0.5000000000000001
#Definition of the planewave basis set
ecut 100.0 # Maximal kinetic energy cut-off, in Hartree
diemac 1000000
#Definition of the SCF procedure
nstep 100 # Maximal number of SCF cycles
# Although this is not mandatory, it is worth to
# precondition the SCF cycle. The model dielectric
# function used as the standard preconditioner
# is described in the "dielng" input variable section.
# Here, we follow the prescription for bulk silicon.
occopt 7
tsmear 0.007
#Definition of the k-point grid
kptrlatt -4 4 4 # In cartesian coordinates, this grid is simple cubic,
and
4 -4 4 # actually corresponds to the so-called 8x8x8
Monkhorst-Pack grid.
4 4 -4 # It might as well be obtained through the use of
# ngkpt, nshiftk and shiftk .
#Gives the number of band, explicitely (do not take the default)
nband 70 # For an insulator (if described correctly as an
insulator
# by DFT), there is no need to include conduction bands
# in response-function calculations
#Exchange-correlation functional
ixc 1 # LDA Teter Pade parametrization
---------------------------------------------------------------------------------------------
But, when I run this code it fails when it reaches the calculation of the
first
perturbation. The end of the output file looks like:
-inwffil : will read wavefunctions from disk file trf1_100Ha_WFK
-P-0000 - newkpt: read input wf with ikpt,npw= 1 62947, make ikpt,npw= 1
62947
==> initialize data related to q vector <==
The list of irreducible perturbations for this q vector is:
1) idir= 1 ipert= 1
2) idir= 2 ipert= 1
3) idir= 3 ipert= 1
4) idir= 1 ipert= 7
5) idir= 3 ipert= 7
6) idir= 1 ipert= 9
7) idir= 2 ipert= 9
8) idir= 3 ipert= 9
9) idir= 1 ipert= 12
10) idir= 3 ipert= 12
================================================================================
The perturbation idir= 1 ipert= 2 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 2 ipert= 2 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 3 ipert= 2 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 1 ipert= 3 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 2 ipert= 3 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 3 ipert= 3 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 1 ipert= 4 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 2 ipert= 4 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 3 ipert= 4 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 1 ipert= 5 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 2 ipert= 5 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 3 ipert= 5 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 1 ipert= 6 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 2 ipert= 6 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 3 ipert= 6 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 2 ipert= 7 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 1 ipert= 8 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 2 ipert= 8 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 3 ipert= 8 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 1 ipert= 10 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 2 ipert= 10 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 3 ipert= 10 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 1 ipert= 11 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 2 ipert= 11 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 3 ipert= 11 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 2 ipert= 12 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 1 ipert= 13 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 2 ipert= 13 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
The perturbation idir= 3 ipert= 13 is
symmetric of a previously calculated perturbation.
So, its SCF calculation is not needed.
--------------------------------------------------------------------------------
Perturbation wavevector (in red.coord.) 0.000000 0.000000 0.000000
Perturbation : displacement of atom 1 along direction 1
Found 2 symmetries that leave the perturbation invariant.
symkpt : the number of k-points, thanks to the symmetries,
is reduced to 106 .
The stderr has:
mpiexec: Warning: tasks 0-127 exited with status 1.
Can anyone tell me what may be wrong?
Thank you,
David.
--
David A. Tompsett
Quantum Matter Group
Cavendish Laboratory
J. J. Thomson Avenue
Cambridge CB3 0HE
U.K.
Tel: +44 7907 566351 (mobile)
Fax: +44 1223 337351
http://www-qm.phy.cam.ac.uk/
- [abinit-forum] Gamma Phonon Calculation Fails, dat36, 10/29/2008
- Re: [abinit-forum] Gamma Phonon Calculation Fails, Anglade Pierre-Matthieu, 10/29/2008
- Re: [abinit-forum] Gamma Phonon Calculation Fails, matthieu verstraete, 10/29/2008
- Re: [abinit-forum] Gamma Phonon Calculation Fails, David Tompsett, 10/30/2008
- Re: [abinit-forum] Gamma Phonon Calculation Fails, Anglade Pierre-Matthieu, 10/29/2008
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