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- From: Anglade Pierre-Matthieu <anglade@gmail.com>
- To: forum@abinit.org
- Subject: Re: [abinit-forum] Space group problem
- Date: Fri, 13 Nov 2009 09:19:07 +0100
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Hi,
Could it be that you have removed too many digit when writing the
coordinates of your atoms ? For Abinit to guess correctly the
symmetries, one usually uses fractional coordinates or decimal numbers
with at least 9 significant digit.
Best,
PMA
On Fri, Nov 13, 2009 at 6:59 AM, Dev Sharma <champbond1983@gmail.com> wrote:
> hi 2 all,
> The space group of ErVo4 is 'I 41/a' where in my output it is, space group
> P1(#1), bravis aP(primitive triclinic),
> And in the visualization, i think my structure is ok. Please help. And
> secondly, i am using the conventional unit cell, even if i am setting
> chkprim 0 or not, it is giving the same space group. where in some other
> cases, due to multiplicity , abinit was asking for chkprim 0.
> Please help
> My input file is listed below
> Thanks in advance
> Dev
> Junior research fellow,
> University of Delhi
> India
>
>
> ndtset 1
>
>
>
>
>
> #Dataset 1 : usual self-consistent calculation
>
> kptopt1 1 # Option for the automatic generation of k points,
>
> # taking into account the symmetry
>
> nshiftk1 1
>
> shiftk1 0.0 0.0 0.0 # These shifts will be the same for all grids
>
>
>
> ngkpt1 1 1 1
>
> prtden1 1 # Print the density, for use by dataset 2
>
> toldfe1 1.0d-1
>
>
>
>
>
>
>
>
>
> # Definition of the unit cell
>
> #The length of the primitive vectors
>
> # 1 Bohr=0.5291772108 Angstroms
>
> # acell 5.003000 5.003000 11.143000 Angstroms
>
> acell 9.454299 9.454299 21.057218
>
> rprim
>
> 1.000000 0.000000 0.000000
>
> 0.000000 1.000000 0.000000
>
> 0.000000 0.000000 1.000000
>
>
>
>
>
> #Definition of the atom types
>
> # 24 kind of atoms
>
> # ['O', 'V', 'Er']
>
> ntypat 3
>
> znucl 8 23 68
>
> chkprim 0
>
> #Definition of tha atoms
>
> natom 24
>
> typat 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 3 3 3 3
>
> xred
>
> 0.146 0.505 0.2054
>
> 0.646 0.005 0.7054
>
> 0.354 0.495 0.7054
>
> 0.854 0.995 0.2054
>
> 0.245 0.396 0.4554
>
> 0.745 0.896 0.9554
>
> 0.255 0.604 0.9554
>
> 0.755 0.104 0.4554
>
> 0.853 0.495 0.7956
>
> 0.354 0.995 0.2946
>
> 0.646 0.505 0.2946
>
> 0.146 0.005 0.7946
>
> 0.755 0.604 0.5446
>
> 0.255 0.104 0.0446
>
> 0.745 0.396 0.0446
>
> 0.245 0.896 0.5446
>
> 0.0 0.25 0.125
>
> 0.5 0.75 0.625
>
> 0.5 0.25 0.375
>
> 0.0 0.75 0.875
>
> 0.0 0.25 0.625
>
> 0.5 0.75 0.125
>
> 0.5 0.25 0.875
>
> 0.0 0.75 0.375
>
>
>
> #Definition of the planewave basis set
>
> ecut 1.0 # Maximal kinetic energy cut-off, in Hartree
>
>
>
>
>
> #Definition of the SCF procedure
>
> nstep 100 # Maximal number of SCF cycles
>
> diemac 12.0 # Although this is not mandatory, it is worth to
--
Pierre-Matthieu Anglade
- [abinit-forum] Space group problem, Dev Sharma, 11/13/2009
- Re: [abinit-forum] Space group problem, Anglade Pierre-Matthieu, 11/13/2009
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