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Re: [abinit-forum] Vacancies implementation in Al2O3


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  • From: Pierre Boulenc <pierre.boulenc@isen.fr>
  • To: forum@abinit.org
  • Subject: Re: [abinit-forum] Vacancies implementation in Al2O3
  • Date: Thu, 16 Mar 2006 15:26:33 +0100

You need to use the International Tables for Crystallography (Space Groups Symmetry) to find all the images of the positions given in Pinto's article and get all the 40 positions. Or you can use a crystal builder which lets you define the space group for your crystal and output all the 40 positions.

Pierre

Stephane BECU a écrit :

Thaks Vincenzo for yoour help,

Actually I know this article but I did not manage to understand why the
authors wrote 7 Al and 9 O positions in Table I. Why 7 Al and 9 O?
Can you tell me more?

Thanks again

Stéphane

-----Original Message-----
From: Vincenzo Fiorentini [mailto:vincenzo.fiorentini@gmail.com] On Behalf
Of Vincenzo Fiorentini
Sent: Thursday, March 16, 2006 1:10 PM
To: forum@abinit.org
Subject: Re: [abinit-forum] Vacancies implementation in Al2O3


there is a good paper on the topic:
Pinto et al., prb 70, 125402 (2004).
the cell is 40 atoms. I estimated a
diagonal dielectric constant (9,9,11).

V. Fiorentini



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Pierre Boulenc

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