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- From: "D. R. Hamann" <drhamann@mat-simresearch.com>
- To: forum@abinit.org
- Subject: Re: [abinit-forum] structural geometry of alfa-Al2O3
- Date: Mon, 11 Jun 2007 13:36:10 -0400
Dear Zhang,
The elastic constants are in Cartesian coordinates. If your Cartesian atom positions are the same using both rhombohedral and hexagonal unit cells, the elastic tensors should be the same. If the one of the cells represents a rotation with respect to the other, the elastic tensors will be different but related by a geometrical transformation that is probably in some textbook on continuum elastic theory.
Don Hamann
waigen zhang wrote:
Dear Lallet,
Thank you for your replies.
Have you tried to calculate the elastic constant? There are several ways to define the structural geometry for alpha-Al2O3 and it seems the nonzero elements in the elastic tensor are different if we choose different geometry.
W.G.Zhang
On 6/9/07, *Lallet François* <francois.lallet@umontreal.ca <mailto:francois.lallet@umontreal.ca>> wrote:
Dear Zhang,
I followed the instruction on webpage
http://cst-www.nrl.navy.mil/lattice/struk/d5_1.html. and I studied
the relaxation of the alpha Al2O3 rhombohedral unit cell with
ionmov=2; optcell=2, ngkpt=2 2 2 and ecut was fixed to 15Ha (I
used PAW pseudopotentials produced with atompaw) in LDA and GGA.
The energy was converged within 0.2eV/atom and the forces relaxed
below 10^-4Ha/(Bohr.atom), which was sufficient to produce relaxed
lattice parameters and internal ionic positions (see Wyckoff
"Crystal Structure" is you have any doubts) in very good agreement
with experiments. I calculated also the bulk modulus by fitting
E(V) with a Murnaghan equation of state and the results are very
good... but I don't know whether the hexagonal unit cell is better
than the rhombohedral one for this purpose...
Best,
F. Lallet
-----Original Message-----
From: waigen zhang [mailto:waigen.zhang@gmail.com
<mailto:waigen.zhang@gmail.com>]
Sent: Fri 6/8/2007 3:52 PM
To: forum@abinit.org <mailto:forum@abinit.org>
Subject: [abinit-forum] structural geometry of alfa-Al2O3
Dear all,
Dose anybody have idea about the structural geometry about
alfa-Al2O3 ?
Should we use the rhombohedral or hexagonal primitive cell for ABINIT
calculation of elastic constant?
I followed the instruction on webpage
http://cst-www.nrl.navy.mil/lattice/struk/d5_1.html.
But still not sure about that. Your suggestion is welcome.
Best,
W.G.Zhang
--
D. R. Hamann
Mat-Sim Research LLC | Deptartment of Physics
P.O. Box 742 | and Astronomy
Murray Hill, NJ 07974 | Rutgers University
phone: 908-370-8079 | 732-445-4381
email: drhamann@mat-simresearch.com
- structural geometry of alfa-Al2O3, waigen zhang, 06/08/2007
- Re: [abinit-forum] structural geometry of alfa-Al2O3, Xavier Gonze, 06/08/2007
- Re: [abinit-forum] structural geometry of alfa-Al2O3, Nuno A. G. Bandeira, 06/08/2007
- RE: [abinit-forum] structural geometry of alfa-Al2O3, Lallet François, 06/09/2007
- Re: [abinit-forum] structural geometry of alfa-Al2O3, waigen zhang, 06/11/2007
- Re: [abinit-forum] structural geometry of alfa-Al2O3, D. R. Hamann, 06/11/2007
- RE: [abinit-forum] structural geometry of alfa-Al2O3, Lallet François, 06/11/2007
- Re: [abinit-forum] structural geometry of alfa-Al2O3, waigen zhang, 06/11/2007
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